Force required to bend sheet metal with a bending brake

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SUMMARY

The force required to bend a piece of .032" thick aluminum (AL) sheet metal using a hand bending brake depends on several factors, including the bend radius and the sharpness of the edge on the brake. For a bend radius of .045" and a desired angle of 110°, the volume of metal being deformed is calculated to be .11 in³. Various online calculators are available to determine the exact force needed for this bending operation, which can be found through a simple search for "Force to Bend Sheet Metal."

PREREQUISITES
  • Understanding of sheet metal properties, specifically aluminum.
  • Familiarity with bending brake operation and mechanics.
  • Knowledge of bend radius and its impact on force requirements.
  • Ability to use online calculators for force calculations.
NEXT STEPS
  • Research the mechanics of bending sheet metal using hand bending brakes.
  • Explore online calculators specifically designed for calculating bending forces.
  • Learn about the effects of different bend radii on force requirements.
  • Investigate the properties of aluminum and how thickness affects bending force.
USEFUL FOR

Metal fabricators, engineers, and hobbyists involved in sheet metal work who need to understand the forces involved in bending operations.

HCaduser
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I want to know the force required to bend a piece of sheet metal in a hand bending brake. The sheet metal is clamped down and then bent upwards to a desired angle. The action is performed in the video below . Let's say I wanted to bend a piece of .032" thick AL 3' long to 110° (given the brake was able to make this degree of bend). How much force would be required to make this bend using this bending method?

 
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"How much force?" Depends on the actual bend radius, how sharp an "edge" you have on the break.
 
"Edge" is a radius of .04" And the bend radius is .045".
 
What's the volume of metal in the bend that is being permanently deformed?
 
.11in^3
 
Last edited:
HCaduser said:
.032" thick AL 3' long
times
HCaduser said:
bend radius is .045".
times 2pi/4
HCaduser said:
6.912in^3
Don't think so.
 

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