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Force required to keep arm in position

  1. Nov 11, 2014 #1
    1. The problem statement, all variables and given/known data
    Lawrence is holding a 9kg dumbbell in his hand with his elbow flexed 90degrees. The horizontal distance from the center of mass of the dumbbell to the center of Lawrence's elbow is 33cm. The horizontal distance from the insertion of his elbow flexor tendons to his elbow is 3cm. If we ignore the mass of Lawrence's arm, how much Force do his elbow flexor muscles have to produce to hold his arm in this position?

    2. Relevant equations
    T = F x r ?

    3. The attempt at a solution
    I drew a diagram and labeled the known values. I am unsure if I should convert the 9kg dumbbell to newtons (or if that is even right to do). The professor has previously converted cm to m, but I found nothing about that in our book. I converted 33cm to 0.33m and 3cm to 0.03m, but also don't know if that is right to do. Also, converted 90degrees to radians: 1.570rad, but once again unsure. I just need some guidance on if I'm doing Anything correctly and what step to take next.
     
  2. jcsd
  3. Nov 11, 2014 #2

    Orodruin

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    Forces are measured in Newton so yes, you have to convert the mass of the dumbell to Newtons (noting of course that it is in a gravitational field).

    The distances you can give in cm, m, yards, or light years - as long as you use the same units for both (resulting in the same unitd for torque, i.e., Ncm, Nm, Nyards, or Nly).
     
  4. Nov 11, 2014 #3

    billy_joule

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    Show us your diagram.
    There was no need to convert degrees to radians..

    What can you tell us about the sum of torques about the elbow?
     
  5. Nov 12, 2014 #4
    Is the 90degrees relevant to the equation?
    I looked over another, similar problem and then did this:
    T = 9kg x 33cm = 88.29N x 0.33m = 29.13Nm
    Then
    29.13Nm / 0.03m = 971.19N

    But the other problem didn't have a value for degrees.
     
  6. Nov 12, 2014 #5

    CWatters

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    An explanation that demonstrates you understand the problem is more important than getting the correct numerical answer. Suppose you made a minor error in the calculation? If you only give an incorrect numerical answer you will score zero. If you explain your working you might still get most of the marks.

    If I was to be picky I would point out that..

    9kg x 33cm = 88.29N x 0.33m

    ..is incorrect because the units don't balance.
     
  7. Nov 12, 2014 #6

    billy_joule

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    Yes.
    Could you answer the question if the arm was at 80 degrees?
    If the arm was at 180 degrees what would the answer be? You should be able to answer that without doing any calculations.
     
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