Force to move a 24 tonne truck one foot in one second

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To move a 24-tonne truck one foot in one second, a constant acceleration of 0.6096 m/s² is required, resulting in a force of approximately 14,630.4 N or 1.524 tonnes-force. The calculations confirm that using the second equation of motion yields this force, assuming the truck starts from rest. There is some confusion regarding the use of "ton" versus "tonne," as the latter is a metric unit of mass, while tonne-force is a non-SI unit for force. Clarification on these units is important for accurate communication in physics discussions.
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The acceleration in one second over one foot distance is 0.6096 m/s2. So, F=m⋅a=24,000×0.6096=14,630.4N

Therefore, the force required to move a 24-tonne truck one foot in one second (from rest):


  • Force = 14,630.4 N
  • ≈ 3,289.5 lbf
  • ≈ 1.492 tonnes-force
Is that correct?
 
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The acceleration would have to be expressed as a function of time and various answers can be gotten for different functions. However, I am going to assume that you mean the acceleration is constant and that the truck started from rest. using second equation of motion, 1/2 at2 - ut=s
u=0, t=1,s=1
substituting, a/2=1,
a=2ft/s2
using F=ma,
F=24 tonne ⊗2ft/s2=48 tonne ft s-2
 
anthraxiom said:
The acceleration would have to be expressed as a function of time and various answers can be gotten for different functions. However, I am going to assume that you mean the acceleration is constant and that the truck started from rest. using second equation of motion, 1/2 at2 - ut=s
u=0, t=1,s=1
substituting, a/2=1,
a=2ft/s2
using F=ma,
F=24 tonne ⊗2ft/s2=48 tonne ft s-2

If we want to find just the force and assuming we want to find the force to push the 24 tonne truck in one second over a distance of one foot, is it around 1.5 tonne?
 
Rev. Cheeseman said:
If we want to find just the force and assuming we want to find the force to push the 24 tonne truck in one second over a distance of one foot, is it around 1.5 tonne?
after conversion I get around 14.683 ton-force
 
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Mass = 24 Mg, in 1 second ; 1 foot = 0.3048 m .
s = u⋅t + ½⋅a⋅t2 ; t = 1 ; u = 0 .
a = 2 * s = 0.6096 = 0.6096 m⋅s-2
F = 24 Mg * 0.6096 = 14.6304 MN = 14630.4 kN
14630.4 / 9.8 = 1524. kg force = 1.524 tonne force.
 
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anthraxiom said:
after conversion I get around 14.683 ton-force

Baluncore said:
Mass = 24 Mg, in 1 second ; 1 foot = 0.3048 m .
a = 2 * s = 0.6096 = 0.6096 m⋅s-2
F = 24 Mg * 0.6096 = 14.6304 MN = 14630.4 kN
14630.4 / 9.8 = 1524. kg force = 1.524 tonne force.

Thank you so much, guys.
 
Baluncore said:
Mass = 24 Mg, in 1 second ; 1 foot = 0.3048 m .
a = 2 * s = 0.6096 = 0.6096 m⋅s-2
F = 24 Mg * 0.6096 = 14.6304 MN = 14630.4 kN
14630.4 / 9.8 = 1524. kg force = 1.524 tonne force.

Sorry, where did 9.8 figure came from?
 
F = m⋅a = m⋅g
g = 9.8 m⋅s-2
 
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Note that the "ton" is a customary unit;
The metric, ISO, or SI "tonne" = 1000 kg.
The "short ton", (common in the USA) = 2000 pounds = 907.184 kg.
The "long ton" (once common in the UK) = 2240 pounds = 1016.047 kg.
It is wise to avoid the unspecified "ton".
 
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Rev. Cheeseman said:
If we want to find just the force and assuming we want to find the force to push the 24 tonne truck in one second over a distance of one foot, is it around 1.5 tonne?
It seems that you are using tonne for force and mass simultaneously.

Copied from:
https://en.m.wikipedia.org/wiki/Tonne

“The tonne (symbol: t) is a unit of mass equal to 1,000 kilograms.
.....
In contrast to the tonne as a mass unit, the tonne-force is not accepted for use with SI.”
 
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