Rev. Cheeseman
- 353
- 21
Thread moved from the technical forums to the schoolwork forums
The acceleration in one second over one foot distance is 0.6096 m/s2. So, F=m⋅a=24,000×0.6096=14,630.4N
Therefore, the force required to move a 24-tonne truck one foot in one second (from rest):
Therefore, the force required to move a 24-tonne truck one foot in one second (from rest):
- Force = 14,630.4 N
- ≈ 3,289.5 lbf
- ≈ 1.492 tonnes-force