Force Vector Problem: Find Magnitude & Direction of F3

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SUMMARY

The discussion centers on solving the Force Vector Problem involving three forces, F1, F2, and F3, where the vector sum equals zero. Force F1 has a magnitude of 26.8 N at an angle of 30.0° to the left of the +y axis, and F2 has a magnitude of 15.2 N along the +x axis. The correct approach to find F3 involves using the equations F1x + F2x + F3x = 0 and F1y + F2y + F3y = 0, along with the Pythagorean theorem to determine the magnitude and direction of F3.

PREREQUISITES
  • Understanding of vector components and their summation
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with Newton's laws of motion
  • Proficiency in using the Pythagorean theorem for calculating magnitudes
NEXT STEPS
  • Review vector addition and decomposition of forces in physics
  • Learn how to apply trigonometric functions to resolve forces into components
  • Study the concept of equilibrium in physics, focusing on net force calculations
  • Practice similar problems involving multiple forces and their resultant vectors
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Students studying physics, particularly those focusing on mechanics and vector analysis, as well as educators looking for problem-solving strategies in force vector problems.

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Homework Statement



Three forces are applied to an object, as shown in the figure. Force F1 has a magnitude of 26.8 Newtons (N) and is directed 30.0° to the left of the +y axis. Force F2 has a magnitude of 15.2 N and points along the +x axis. A third force F3 is applied such that the vector sum of the three forces is 0 N. What are (a) the magnitude and (b) direction of this third force? Specify the direction as a positive angle relative to the negative x axis, as shown in the figure.

Picture: http://s236.photobucket.com/albums/ff132/airpenny123/?action=view&current=ch01p_46.gif

Homework Equations



F3X = F1X + F2X
F3Y = F1Y + F2Y

F3= √F3X^2 + F3Y^2


The Attempt at a Solution



F1X = (-26.8N)(.8660)
F1X = -23.21N

F2X = 15.2N

F3X = -23.21N + 15.2N = -8.01N

F1Y = (26.8N)(0.5)
F1Y = 13.4N

F2Y = 0

F3Y = 13.4N + 0 = 13.4N

I found the components of F3X = -8.01 and F3Y = 13.4. When I plug the components into: F3= √F3X^2 + F3Y^2, I get 15.6115 N, which apparently is wrong. I've been on this problem forever and I don't know what I'm doing wrong.

As for this part of the question: "Specify the direction as a positive angle relative to the negative x axis, as shown in the figure." I am completely lost...

Thanks for any help.
 
Last edited:
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Welcome to PF :smile:

I see two problems.

Since the vector sum is zero, the equations should read

F1x + F2x + F3x = 0​

and similarly for the y-components.

Also, calculating the x-component of F1 does not involve cos(30).

As for this part of the question: "Specify the direction as a positive angle relative to the negative x axis, as shown in the figure." I am completely lost...

They just mean the angle from the -x direction.
 
why is that my prof taught us to get first the force sumation in X and in Y and use phytagorean theorem and then get the direction ..
 
Welcome to Physics Forums.
dgiordan said:
why is that my prof taught us to get first the force sumation in X and in Y and use phytagorean theorem and then get the direction ..
That is pretty much how you do this sort of problem, or anything that involves adding vectors. I'm not sure what specifically is confusing you about it?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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