Calculating Work Using a Force vs Distance Graph

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SUMMARY

This discussion focuses on calculating work using a force versus distance graph, specifically applying the equation W = (Force component * displacement). The participant calculated work done over two segments: from 5m to 10m with a constant force of 30N resulting in 150J, and from 10m to 15m where the force varied from 30N to approximately 18N, yielding an additional 120J. The total work calculated is 270J, confirming the accuracy of the calculations presented.

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  • Understanding of work-energy principles in physics
  • Familiarity with area calculations for geometric shapes
  • Knowledge of force and displacement concepts
  • Ability to interpret force vs distance graphs
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  • Learn how to calculate areas under curves for varying forces
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Le_Anthony
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Homework Statement


queston 9.png

Homework Equations


W=(Force component*displacement)

The Attempt at a Solution


This problem uses a graph to find the Work. So I used area equations to find the Work. From 5m to 10m the Force is constant 30N. Which is applied over a displacement of 5m. So the work done from 5m to 10m is 150J. Next, from 10m to 15m the work varries. Its initially 30N then it drops down to roughly 18N. So using a triangle, .5*(30N+18N)*(5m)=120J

Answer is 270J??
 
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Hi Le:

Your answer looks OK to me.

Regards,
Buzz
 
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Buzz Bloom said:
Hi Le:

Your answer looks OK to me.

Regards,
Buzz
Thanks Buzz!
 
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