Worker Sim Pulma Sheen: Solving a Pulley Problem

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Homework Help Overview

The problem involves a pulley system where a worker attempts to lift a 5000 N box using a force of 500 N. The question seeks to determine how much rope the worker must pull to achieve this lift.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of work equations, specifically questioning the relationship between work done on the object and the work done by the worker. There is an attempt to equate these to find the distance pulled.

Discussion Status

Some participants express uncertainty about the correctness of their approach and the equations used. There is acknowledgment of a potential error in the problem setup, with suggestions that the correct answer may not be among the provided options. The discussion remains open with no explicit consensus reached.

Contextual Notes

Participants note that the problem was sourced from a physics teacher for a home retake test, indicating a possible context of academic assessment and the implications of errors in the problem statement.

Just_enough
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Repost since it was removed from double questions.
1. Homework Statement

Worker Sim Pulma Sheen uses a system of pulleys to lift a 5000 N box 2 meters while pulling on the rope with a force of 500 N. This means the worker had to pull how much rope from the pulley system?
a) 0.2m. b) 2m c) 5m d) 10m e) 30m

Homework Equations


W = F*D?

The Attempt at a Solution


[/B]
I tried to find the work of the obj then set it equal to the work done on the person (pulling) and divide by force to find distance, and got 20... is this not the right equation?
 
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Just_enough said:
I tried to find the work of the obj then set it equal to the work done on the person (pulling) and divide by force to find distance, and got 20... is this not the right equation?
You are correct.
 
Doc Al said:
You are correct.
what equation should I use then?
 
Just_enough said:
what equation should I use then?
Your analysis is correct as is. You used the correct equation. The correct answer is not among the choices--not your fault.

Where did you get the problem?
 
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Doc Al said:
Your analysis is correct as is. You used the correct equation. The correct answer is not among the choices--not your fault.

Where did you get the problem?
Oh haha, thought you mean I am am correct on not being correct. I got it from my physics teach for a home retake test on our quiz...
 
Just_enough said:
I got it from my physics teach for a home retake test on our quiz...
Maybe you'll get extra credit for pointing out his error. :smile:
 
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Doc Al said:
Maybe you'll get extra credit for pointing out his error. :smile:
I wish, it's hard to get in touch with him.
 

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