Calculation of work involving unit vectors

Click For Summary
SUMMARY

The calculation of work done on a grocery cart subjected to a force of f = (30N)i - (40N)j during a displacement of s = (-9.0m)i - (3.0m)j results in a total work of -150J. The work is computed by applying the dot product of the force and displacement vectors, yielding W = f · s = (30 * -9) + (-40 * -3) = -150J. The absence of unit vectors in the final answer is due to work being a scalar quantity, which is the sum of the individual work components along the x and y axes.

PREREQUISITES
  • Understanding of vector operations, specifically dot products
  • Familiarity with scalar quantities in physics
  • Basic knowledge of force and displacement in physics
  • Ability to perform calculations involving unit vectors
NEXT STEPS
  • Study the concept of dot products in vector mathematics
  • Learn about scalar and vector quantities in physics
  • Explore the implications of work-energy principles in mechanics
  • Practice problems involving force and displacement vectors
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and vector analysis, as well as educators looking to clarify concepts related to work and energy.

bakakun028
Messages
1
Reaction score
0

Homework Statement



A loaded grocery cart is rolling across a parking lot in a strong wind. You apply a constant force f = (30N)i - (40N)j to the cart as it undergoes a displacement s = (-9.0m)i - (3.0m)j
How much work does the force you apply do on the grocery cart?


Homework Equations





The Attempt at a Solution



I was assuming all I needed to do was do F*d for the i unit vector and j unit vector like so:
W = (F*d)i + (F*d)j = (30*-9)i + (-40*-3)j = (-270J)i + (120J)j

But according to the answer book, the final work has no unit vectors involved and it is the sum of those two calculated works.

-270J + 120J = -150J

How come the unit vectors are not included in the answer? Also, how come we can simply sum up the x and y W's and works like that? I know it has something to do with work being a scalar...
 
Physics news on Phys.org
Dot product gives you a scalar quantity. Also- i.i=1 not i.
 
hi bakakun028! welcome to pf! :smile:

yes, work done is always a scalar quantity (an ordinary number) :wink:
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
7K
Replies
12
Views
2K
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K