- #1

sandy.bridge

- 798

- 1

Hey all,

I am merely looking for clarrification as to what happens with the circuit that I have provided an image of. Please assume all elements are ideal (for simplicity). I come here for assurance as I cannot seem to find it anywhere else. Thanks in advance!

Thyristor T1 is fired at some angle and then it begins to conduct. The capacitor begins to charge until plate A in the schematic reaches the sources potential. If thyristor T3 is then turned on at this point, it provides a path for the current to discharge through T3. The current is a resonant oscillation through T3. Once the voltage across the capacitor has become fully reversed, D2 is forward biased. Once the forward current through T1 is less than the current through D2, T1 is such off. The capacitor is then allowed to discharge through D1, and then recharge from the load. Once the capacitor attains the potential of the source, it no longer conducts a current, and all of the current as an entirety remains in the free-wheeling diode.

Thanks again for any clarrifications.

I am merely looking for clarrification as to what happens with the circuit that I have provided an image of. Please assume all elements are ideal (for simplicity). I come here for assurance as I cannot seem to find it anywhere else. Thanks in advance!

Thyristor T1 is fired at some angle and then it begins to conduct. The capacitor begins to charge until plate A in the schematic reaches the sources potential. If thyristor T3 is then turned on at this point, it provides a path for the current to discharge through T3. The current is a resonant oscillation through T3. Once the voltage across the capacitor has become fully reversed, D2 is forward biased. Once the forward current through T1 is less than the current through D2, T1 is such off. The capacitor is then allowed to discharge through D1, and then recharge from the load. Once the capacitor attains the potential of the source, it no longer conducts a current, and all of the current as an entirety remains in the free-wheeling diode.

Thanks again for any clarrifications.