Forces: acceleration with a sun yacht

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Homework Help Overview

The problem involves a "sun yacht," a spacecraft propelled by sunlight, with a focus on calculating acceleration, distance traveled, and final velocity based on given forces and mass.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law to find acceleration and express confusion regarding the kinematic equations needed for calculating distance and velocity over time.

Discussion Status

Some participants have provided guidance on using kinematic equations to relate acceleration, time, and velocity. Others express uncertainty about their understanding of these equations and their application to the problem.

Contextual Notes

There is mention of missing familiarity with kinematic equations, which may be affecting participants' ability to progress in the problem-solving process.

wegman14
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[SOLVED]Forces: acceleration with a sun yacht

Homework Statement


Sunjamming. A “sun yacht” is a spacecraft with a large sail that is pushed by sunlight. Although such a push is tiny in everyday circumstances, it can be large enough to send the spacecraft outward from the Sun on a cost-free but slow trip. Suppose that the spacecraft has a mass of 700 kg and receives a push of 18 N. (a) What is the magnitude of the resulting acceleration? If the craft starts from rest, (b) how far will it travel in 1 day and (c) how fast will it then be moving?


Homework Equations


F=Ma
V=ma


The Attempt at a Solution


I think part a is correct, part b i am lost on, and part c just doesn't seem to make sense, it seems too fast
a) a= 18/700= .025 m/s^2


c) 700x.025=17.5 m/s?
 
Last edited:
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Where did you get V=ma? Part a) is ok, But to find a velocity after one day you want to find a relation between acceleration time and velocity. For b) you want a relation between acceleration time and distance. They are just kinematic equations. Like v(t)=v(0)+a*t.
 
its still not making sense to me, probably because i don't have the kinematics equations
 
actually nvm i got it, thanks for the help
 
t= 86400 seconds
V(o)tx(1/2)at
9331200 m

V=0+(at)

2160m/s
 

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