Forces acting on two stacked blocks

Click For Summary
SUMMARY

The discussion centers on calculating the force required to accelerate a 1.5 kg block on top of a 7.5 kg block, both connected by a cord to a pulley, with no friction present. The necessary horizontal force, denoted as F, must exceed the tension (Ft) in the cord to ensure the bottom block accelerates leftward at 2.5 m/s². The analysis confirms that the only horizontal force acting on the top block is the tension Ft, while the bottom block experiences a greater force F to maintain the system's acceleration.

PREREQUISITES
  • Understanding Newton's Second Law of Motion
  • Familiarity with concepts of mass and acceleration
  • Knowledge of tension in a pulley system
  • Basic principles of frictionless surfaces
NEXT STEPS
  • Study Newton's Second Law applications in multi-body systems
  • Learn about tension forces in pulley systems
  • Explore frictionless motion scenarios in physics
  • Investigate the effects of varying mass on acceleration in connected systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for examples of force analysis in multi-body systems.

manaXmizery
Messages
3
Reaction score
0

Homework Statement


A 1.5 kg block rests on top of a 7.5 kg block which are attached using a cord to a pulley - there is no friction anywhere. What force must be applied to the bottom block so the top block accelerates to the right at 2.5 m/s^2?

Homework Equations


m1 = 1.5kg
a(to the right) = 2.5 m/s^2
m2 = 7.5kg

The Attempt at a Solution


Since we are interested in finding the horizontal force F , I neglected all the forces acting vertically on the two blocks mainly the normal Force , Fn and the weights of them . Am i right in assuming that :

1) there is no friction between the two blocks and as such , the only force acting horizontally on the top block is the tension Ft towards the right ?

2) for the bottom block , I have to assume that the force towards the left , F must be greater than the tension , Ft ?

Thanks in advance.

Regards,

Steve
Untitled.png
 
Physics news on Phys.org
1) Correct.

2) If F was not larger than the tension, would m2 be accelerating?

Of course, an underlying assumption that you have not mentioned is that m2 will be accelerating to the left at 2.5 m/s^2 in order for the string length to be constant.
 

Similar threads

Replies
13
Views
3K
Replies
2
Views
2K
Replies
15
Views
3K
Replies
16
Views
3K
Replies
17
Views
4K
Replies
1
Views
3K
  • · Replies 23 ·
Replies
23
Views
3K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
20
Views
2K
Replies
17
Views
2K