- #1

- 1

- 0

## Homework Statement

Assume you are on a planet similar to earth where the acceleration of gravity is 10m/s^2 and the positive directions for displacement velocity and acceleration are upward. At t=0sec., an elevator is at a displacement of x=0 with a velocity of v=0m/s. A student whose weight is 400N stands on a scale in an elevator and records the scale reading as a function of time. The data is shown below:

0-5s--------400N

5-10s-------500N

10-15s------600N

15-20s-----0N

g) What is the displacement of the elevator

above the starting point at the end of the

fourth 5 s interval (at 20 s)?

Answer in units of m.

I was only completely sure about a and b, for a the direction is up and for b the mass is 40kg. I obviously don't want just answers, but steps and hopefully explanations to go along with it.

## Homework Equations

Vf^2 = Vi^2 + 2a X

X = ViT + 1/2 a t ^2

## The Attempt at a Solution

Let

a = acceleration

X = displacement

Vi = Initial Velocity

D(X) = Displacement for time interval

Interval : 0 - 5

a = 0

v = 0

X = 0

Int : 5-10

a = 2.5

v = 12.5

X = 0 + 1/2 (2.5) (5) ^2 = 31.25 m

int : 10-15

a = 5

v = 37.5

X = (37.5)(5) +1/2*(5)(5)^2 +31.25 = 281.25 m

int : 15-20

a= -10

v = -12.5

X = (281.25) + (-12.5)(5) + (1/2)*(-10) (5)^2 = 93.75 m

I submit 93.75 as my final answer and it was wrong. Any help or ideas?