Forces : Man in a lift on a scaler

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Homework Help Overview

The problem involves a man standing in a lift on weighing scales, with a focus on how the scales register weight under different conditions of lift movement. The subject area includes forces, specifically gravitational force and normal force, and their relation to mass and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the man, including gravitational force and normal force. There are attempts to apply Newton's second law (F=ma) to determine the scale readings in various scenarios of lift movement.

Discussion Status

Some participants are questioning the correctness of initial calculations and are seeking clarification on the forces involved. There is an ongoing exploration of how to relate gravitational force to the readings on the scales, with multiple interpretations of the problem being discussed.

Contextual Notes

Participants are navigating the distinction between mass and weight, and the implications of acceleration due to gravity in the context of the problem. There is a mention of needing to express answers in Newtons rather than kilograms.

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Homework Statement


A man of mass 70 kg stands in a lift on a set of weighing scales. The scales are calibrated in Newtons. Assuming that g=10N kg -1
What weight will the scales register when the :

a) lift is static
b)lift accelerates down at 10 ms-2
c)lift accelerates up at 10 ms-2


Homework Equations



F=ma


The Attempt at a Solution



a)
F=ma
F= 70 x 0
F=70

b) accelerates down at 10ms -2

F=ma
F=70 /10
F=7

70-7=63

c) accelerates up at 10 ms -2

70 + 7 = 77

Is this correct ?

Thanks,
dave
 
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Can someone please help me ?
 
davedays said:
Is this correct ?
No, your answers are not correct. First identify all the forces acting on the man. (One of those forces will equal the scale reading.) Then apply ΣF = ma to each case.

Don't forget to give your answers in Newtons, not kg.
 
I don't understand you, sorry. Can you explain again please ?

Is F=ma all I need here ?

I am not sure, however I really want to solve it :)
 
davedays said:
I don't understand you, sorry. Can you explain again please ?
What forces act on the man? (Hint: Two forces act on him.) What direction do they act?

Is F=ma all I need here ?
Yes. Realize that F stands for the net force.
 
So I think it would be gravity acting down and also the normal force pushing him up, correct ?

Knowing that in the first case I subtract and in the second case I add the forces right ?

However I still do not get the connecting between 'g' and the question. :(
 
davedays said:
So I think it would be gravity acting down and also the normal force pushing him up, correct ?
Exactly. And realize that the normal force is what the scale measures.

Knowing that in the first case I subtract and in the second case I add the forces right ?
Just use up as + and down as -. Using that convention, ΣF = N - W.

However I still do not get the connecting between 'g' and the question.
You are given the mass but need the weight (to apply F=ma). That's where 'g' comes in.
 
Ill try do a then :

if the GF is pushing him down and NF is pushing him up then his weight is 70N cause the gravity force is greater by 70 N

Second one:
If the lift is going down then the gravity force must he smaller by 10 :

70-10 = 60 N

Third one :

vice versa

70+10=80 N

Am I thinking correct at this time ?

By the way I really appreciate your help and patience here.
 
davedays said:
Ill try do a then :

if the GF is pushing him down and NF is pushing him up then his weight is 70N cause the gravity force is greater by 70 N
First things first: If the man's mass is 70 kg, what is the GF on him? (The gravitational force is the same in all three cases, as gravity isn't changing.)
 
  • #10
it must be zero cause he's not going up, right ?
 
  • #11
The man is 70 kg, and there's a gravitational force acting down on him, with this in mind F=m(man)*a(?) even though the elevator isn't accelerating what other acceleration is there?
Keep in mind gravity is in m/s^2.
 
  • #12
davedays said:
it must be zero cause he's not going up, right ?
No. I asked about the gravitational force acting on the man. That's certainly not zero! How do you compute the force of gravity? (That's where you use 'g'.)
 

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