Forces on a Truss Homework: Find Tension/Compression

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Homework Help Overview

The discussion revolves around analyzing forces in a truss structure, specifically focusing on determining tension and compression in its members. The original poster describes a scenario involving forces applied at specific points and the geometry of the truss system.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply equilibrium equations to find forces at various points, including moments and force summations. Some participants question the correctness of the calculations and the assumptions made regarding the forces acting on the truss members.

Discussion Status

Participants are actively engaging with the original poster's calculations, providing feedback on specific steps and suggesting areas where errors may have occurred. There is an ongoing exploration of the problem, with some guidance offered regarding potential mistakes in the calculations.

Contextual Notes

There are indications of missing information, such as the original poster's drawings, which are referenced but not provided. The discussion also highlights the complexity of the truss system and the need for careful consideration of forces and moments.

Bradracer18
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Homework Statement



Ok, you'll have to wait for my picture. Basically we are doing trusses, and I'm not sure where I'm going wrong here.

We are to find the tension/compression in each member(line) of the truss.

Ok, from my picture. F1 is directly at B(in neg y direction), and is 2800N. F2 is at point D(in the neg x direction) and is 2100N.

The distances between A&B, and B&C are 4m. A is a pin system(basically has x and y forces)...and C is held up by a cable(I believe only supports in the y direction).

I also drew another picture, which consists of little circles on each joint, and arrows pointing in the directions of the tensions(and forces acting on the "circles").

Homework Equations





The Attempt at a Solution



Ok, I'm only going to post some of this, to see if I started correctly(where I think I messed up).

So, from my picture, I took overall equilibrium. So, I chose to sum moments about point A=0(with a counter-clockwise rotation I chose).

moments at pt A = 0= 8Cy -2800(4) - 2100(3.4641)
Cy = 1259.33N up

Sum Forces in +x direction=0

Ax - 2100 = Ax=2100N to the right

Sum forces in +y direction = 0

Ay + Cy - 2800 = Ay = 1540.67N up

If this is correct, then I'll post more. Next, I drew that other picture, and started at points and found the tension(as I draw them all in tension to begin with) at each point.

Thanks,
Brad

View attachment problem 6.bmp
 
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Looks okay to me.
 
For point A:

Sum Forces in +x=0:

Tab + Tadcos(60) =0 Tab = -3558.02N
Sum Forces in +y=0:

Ay(or 1540.67) - Tadsin(60) = 0 Tad = 1779.01N

I'll stop here again too.

The book says Tab = 2.38kN and Tad = 0.567kN

So, what did I do wrong?
 
Is this portion correct?
 
trying to do another one of these now...so any help would be nice:)
 
Is my drawing or the last post not clear...I'd like to know where I've went wrong. I'll do the calculations, I can't find any other way to do them, as of now...need to know if I'm right up to this point.
 
Bradracer18 said:
Is my drawing or the last post not clear...I'd like to know where I've went wrong. I'll do the calculations, I can't find any other way to do them, as of now...need to know if I'm right up to this point.
You have a math error up front when you calculated C_y. Right equation, careless math.

Then you left out the A_x reaction when you summed forces in x direction at A.

And one of those members at A will not be in tension.
 
Ok...I figured it out...I guess I didn't go over my work as carefully as I thought I did. Thanks for the help...I'm sure by the end of the day, I'll have another one of these posted...ha ha...Thanks again!
 

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