Imagine a vertically placed clock. What forces have an effect on the object when it is in the position of 3am?
No need od equations i guess.
The Attempt at a Solution
So I figured out that when the object is in the position of 12am then weight of the object is the final centripetal force.
Also when it is in the position of 6am then final centripetal force is the force of rope which has to compensate the weight of the object.
But when it is in the position of 3am then weight is perpendicular to centripetal force and I know(or at least I think it's correct) that centripetal force should be the resultant of more forces. But I cant figure out any other forces in there.
Can someone help me a bit please? Thanks
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