- #1

- 23

- 0

Determine the location of the center of mass of a "L" whose thin vertical and horizontal members have the same length L and the same mass M. Use the formal definition to find the x and y coordinates, and check your result by doing the calculation with respect to two different origins, one in the lower left corner at the intersection of the horizontal and vertical members and one at the right end of the horizontal member.

(a) origin at the lower left

xcm =

ycm =

(b) origin at the right end of the horizontal member

xcm =

ycm =

Relevant Equations:

The center of mass can be found by (m1r1+m2r2)/2

Attempt at solution:

Since I have not gotten part A, I have not been able to attempt part B.

Since I am not given a mass, I have simply tried doing (r1+r2)/2, or (L+L)/2 in this case, but it is not the right answer. Can somebody please tell me what I'm doing wrong?