Formula deduction V2 = V02 + 2g(y - y0)

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In summary, the conversation is about a person seeking help with making a deduction from the formula V2 = V02 +- 2g(y - y0). They are unsure about the meaning of "making the deduction" and are seeking clarification on the equation and where they are getting stuck.
  • #1
iZnoGouD
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I need to make the deduction of this formula V2 = V02 +- 2g(y - y0)
Could you guys help me? this is so hard for me :confused:
 
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  • #2
iZnoGouD said:
I need to make the deduction of this formula V2 = V02 +- 2g(y - y0)
Could you guys help me? this is so hard for me :confused:

Welcome to PF, iZnoGouD! :smile:

Could you clarify what you mean by "making the deduction"? I'm not clear what you're being asked to do.

And, to clarify for myself, the equation is:
[itex]V^2 = V_{0}^2\pm 2g(y-y_0)[/itex]

Correct?

And finally, where are you getting stuck? Can you show us your work so far?
 

1. What does the formula V2 = V02 + 2g(y - y0) represent?

The formula represents the final velocity (V2) of an object with an initial velocity (V02), undergoing constant acceleration (2g) over a vertical displacement (y-y0).

2. How do you calculate the value of V2 using this formula?

To calculate the value of V2, you first need to determine the values of V02, g, y, and y0. Then, plug these values into the formula and solve for V2.

3. What units should be used for the variables in this formula?

The initial velocity (V02) and final velocity (V2) should be in meters per second (m/s), acceleration (g) should be in meters per second squared (m/s^2), and the vertical displacement (y and y0) should be in meters (m).

4. Can this formula be used for any type of motion?

No, this formula is specifically used for calculating the final velocity of an object undergoing constant acceleration in a vertical direction. It cannot be applied to other types of motion, such as circular motion or variable acceleration.

5. How is this formula derived?

This formula is derived from the equations of motion, specifically the equation v^2 = u^2 + 2as, where v is final velocity, u is initial velocity, a is acceleration, and s is displacement. By substituting a vertical displacement (y-y0) for s and using the acceleration due to gravity (g), we arrive at the formula V2 = V02 + 2g(y - y0).

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