Formula involving the change in a kinetic energy

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To determine the change in kinetic energy of a 4kg box subjected to a 120 N force at a 30-degree angle, the work done by the force can be calculated using the formula W = F * d * cos(θ), where θ is the angle of the force. The horizontal component of the force is 120 N * cos(30°), and the vertical component is 120 N * sin(30°). Assuming the initial velocity is zero, the change in kinetic energy equals the work done on the box as it moves 8 meters horizontally. If gravity is considered, potential energy can be calculated as V = mgh, but if not, it remains zero. The final kinetic energy can be found by equating the total work done to the change in kinetic energy.
electrical_ck
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I'm looking for a formula involving the change in a kinetic energy, I have a 120 N force applied at an angle of 30 degrees above the horizontal to a 4kg box. The box moves a horizontal distance of 8 meters. The change in the kinetic energy of the box is:

Just looking for a formula to figure this one out
 
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The work done by the force on the box=Change in kinetic energy of the box.
 
Hi,...What equations do you have for work? Calculate the vector components of the 120N force. This will simplify the problem for you.
 

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If you assume the initial velocity is 0, you know that the final energy of the box is E = K + V, K being the kinetic energy and V being the potential. If gravity is involved, your potential V is mgh. If not, it's 0. You also know that your total energy, or the work done to the box, is equal to F \cdot d\overrightarrow x. Break down the force into its components to determine the work done.
 
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