Fortran 90 very basic question : else if statement

[fluidistic]

Hi there,
I've tried all I could in order to complete a very simple and basic program that finds the roots of any quadratic binomial.
You have to enter the coefficients a, b and c and it would find the roots. I could do that, but a problem occurred if I typed a=0. Of course if a=0 the binomial is not quadratic (and not even a binomial), so I wanted to let it know to the user of the program. Here my problems started... I don't know how to insert in my program that if a=0 then a message would appear saying that it isn't a quadratic binomial.
Here it comes :

Program findroot
implicit none

Real(8) :: a,b,c,delta,z,y,g


Write(*,*)'Enter a, b and c'
Read(*,*)a,b,c


if (a=0) then
write(*,*)'This is not a quadratic binomial'
endif


delta=b**2-4*a*c

If (delta>=0) then
z=(-b+sqrt(delta))/(2*a)
y=(-b-sqrt(delta))/(2*a)
Write(*,*)'The roots are',z,y


Elseif (delta<0) then
write(*,*)'The binomial has no root in R but in C its roots are',-b,'+i',sqrt(-delta)/(2*a),'and',-b,'-i',sqrt(-delta)/(2*a)



endif




End program findroot

I'm almost sure that I cannot type endif and then type if...
But I tried many other things like

if (a=0) then
write(*,*)'This is not a quadratic binomial'



delta=b**2-4*a*c

elseIf (delta>=0) then
z=(-b+sqrt(delta))/(2*a)
y=(-b-sqrt(delta))/(2*a)
Write(*,*)'The roots are',z,y


Elseif (delta<0) then
write(*,*)'The binomial has no root in R but in C its roots are',-b,'+i',sqrt(-delta)/(2*a),'and',-b,'-i',sqrt(-delta)/(2*a)



endif

and changing the order of the if statements... I always get errors and the program doesn't compile.
Any help is appreciated.

Note: If I erase the if (a=0) statement the program works well. (it compiles and find roots unless I type a=0).

 

[montoyas7940]

Ok. It has been a long time (fortran77) but try an else in place of your first endif.

 

[fluidistic]

Thanks for the answer.
It doesn't work, I get an error : Unexpected ELSE statement.
By the way the other error is : Error: Syntax error in IF-expression at (1). (It points out the "a" in "if (a=0) then". I don't see why it is a syntax error... strange.

 

[montoyas7940]

Look at this and see what you think. It compiled on a G77 compiler. It needed a == in the
if (a=0) then

there is still a problem with ending the prog after the message on a=0

Program findroot

Write(*,*)'Enter a, b and c'
Read(*,*)a,b,c


if (a == 0) then
write(*,*)'This is not a quadratic binomial'
delta = b**2-4*a*c
endif

If (delta >= 0) then
z = (-b+sqrt(delta))/(2*a)
y = (-b-sqrt(delta))/(2*a)
Write(*,*)'The roots are',z,y


Elseif (delta<0) then
write(*,*)'The binomial has no root in R but in C its roots

are',-b,'+i',sqrt(-delta)/(2*a),'and',-b,'-i',sqrt(-delta)/(2*a)

endif

End program



There are some variable declaration differences between my compiler and your also
so ignore my lack of declaration. I am still messing with it so hang with me.

 

[montoyas7940]

how about this?

Program findroot

Write(*,*)'Enter a, b and c'
Read(*,*)a,b,cif (a == 0) then
write(*,*)'This is not a quadratic binomial'
goto 90
endif

delta = b**2-4*a*c
If (delta >= 0) then
z = (-b+sqrt(delta))/(2*a)
y = (-b-sqrt(delta))/(2*a)
Write(*,*)'The roots are',z,yElseif (delta<0) then
write(*,*)'The binomial has no root in R but in C its roots

are',-b,'+i',sqrt(-delta)/(2*a),'and',-b,'-i',sqrt(-delta)/(2*a)

endif
90 write(*,*)'Goodbye'
End program

 

[fluidistic]

Thanks a lot montoyas!
It works great... I forgot that 2 signs "=" were needed. That's nice.
What about this :

100 Write(*,*)'Enter a, b and c'
Read(*,*)a,b,cif ( a==0 ) then
write(*,*)'This is not a quadratic binomial, try again'
goto 100
endif

:)

 

[montoyas7940]

That's even better. And you are welcome.

That was a fun trip in the way back machine.