DrChinese
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1. Your first state - exactly as you have it - is one which can be prepared for each and every run*. That does not lead to DCES statistics on unbiased bases for a BSM. So either you should be presenting this in some different form*, or it is excluded experimentally. Which?Morbert said:1. Alice and Bob measure in the +/- basis and get the result ++, projecting the state (rule 7) onto $$\ket{++}_{14}\ket{--}_{23}$$The probability that Victor's BSM gets the result ##\phi^-## for these runs is (rule 6)$$p(\phi^-) = |\bra{\phi^-}--\rangle|^2 = 0$$2. This can be shown by expanding ##\ket{--}## in the Bell basis: $$\ket{--} = (\ket{\phi^+} - \ket{\psi^+})/\sqrt{2}$$Consistent with the Ma experiment, Victor can't get the result ##\phi^-## when Alice's and Bob's measurements are correlated in the +/- basis.
2. There is no such thing as what you describe here. A Product state of 2 particles is not equivalent to a expression of entangled states of those same particles. But the reverse can be true: An entangled state can lead to a product state of 2 particles.
BTW: your simplistic rule references are useless for these situations. We're discussing entangled systems of 2 and 4 particles, which are not discussed in the "7 rules".
*Presumably not a 4-fold Product state.
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