Four Bugs Differential Equation

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Homework Help Overview

The problem involves four bugs walking on a flat surface, starting from specific coordinates and following each other in a counterclockwise direction. The original poster seeks to demonstrate that the motion of one bug satisfies a particular differential equation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use a substitution method to solve the differential equation but expresses uncertainty about the correctness of the equation itself and the approach taken. Some participants question the validity of the differential equation provided, noting that it simplifies to a constant value, which may not be interesting. Others seek clarification on the reasoning behind this simplification.

Discussion Status

The discussion is ongoing, with participants exploring the validity of the differential equation and the implications of its simplification. There is a mix of attempts to clarify the problem and to address potential errors in the original statement.

Contextual Notes

Participants note that there may be inaccuracies in the graphical representation associated with the problem, suggesting that it requires adjustments to align with the described motion of the bugs.

simpleman008
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Homework Statement



Four bugs are walking on a flat surface. They start at the four points (1,1), (1,-1), (-1,1), and (-1,-1) and begin walking counterclockwise, each one following the next. Show that the motion of bug A, who starts at (1,1), satisfies the equation [tex]\frac{dy}{dx}[/tex]= [tex]\frac{y-x}{x-y}[/tex] and solve using an appropriate substitution.

Homework Equations



After some extensive research, I've found the same problem on another website (http://legacy.lclark.edu/~istavrov/diffeq-revsheet1-09.pdf)
that states the motion of the bug starting from (1,-1) satisfies [tex]\frac{dy}{dx}[/tex]= [tex]\frac{y-x}{x+y}[/tex] and that each bugs motion can be shown by the graph:
4bs.png
.

The Attempt at a Solution


A hint from the website, as well as from my teacher, was given saying that y=ux would be the most viable substitution. So starting there I have
[tex]y=ux => dy=xdu + udx[/tex]
[tex]\frac{xdu + udx}{dx}[/tex] = [tex]\frac{ux-x}{x-ux}[/tex]

which after some algebra leads me to:
[tex](x-xu+u)du[/tex]= [tex](u^{2}+u-1)dx[/tex]
This is where I'm stuck, and it doesn't even help me with the first part about proving WHY dy/dx is what it is (i have ideas floating around in my head but nothings clicking yet or coming together in any meaningful way). Any and all help is greatly appreciated!
 
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Are you sure the equation for the first part is right? Because [tex]\frac{y-x}{x-y}=-1[/tex] which doesn't make for a very interesting differential equation
 
Office_Shredder said:
Are you sure the equation for the first part is right? Because [tex]\frac{y-x}{x-y}=-1[/tex] which doesn't make for a very interesting differential equation

Yes that is how he had it written, but why did you put it equal to -1?
 
Also let it be noted that the graph I included obviously isn't correct cause it needs to be rotated 45 degrees
 

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