Finding Limits in Fourier Series: How Do the Left and Right Hand Limits Work?

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SUMMARY

The discussion focuses on deriving the left and right hand limits for a piecewise function defined in the context of Fourier series. The function is defined as f(t) = t² for 0 < t < π and f(t) = 0 for π < t < 2π. As t approaches π from the left, the limit is π², while approaching from the right yields a limit of 0. This illustrates the discontinuity at t = π, which is crucial for understanding the behavior of Fourier series at points of discontinuity.

PREREQUISITES
  • Understanding of piecewise functions
  • Familiarity with limits in calculus
  • Basic knowledge of Fourier series
  • Concept of continuity and discontinuity in functions
NEXT STEPS
  • Study the concept of limits in calculus, focusing on left-hand and right-hand limits
  • Explore the properties of piecewise functions and their continuity
  • Learn about Fourier series and their applications in signal processing
  • Investigate the implications of discontinuities in Fourier series convergence
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Students studying calculus, particularly those focusing on limits and Fourier series, as well as educators looking to enhance their teaching of these concepts.

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Homework Statement



Please see attached image. From the given information, I am having trouble deriving the left and right hand limits, I just can't figure out what these are...

http://img176.imageshack.us/img176/9334/fstih3.png

Homework Equations



None needed.

The Attempt at a Solution



In the solution, t is chosen as pi, which I understand. But I just can't figure out how these left and right hand limits are found. Are these limits somehow derived from limits of integration?

Here is the solution.

http://img176.imageshack.us/img176/2899/fst2yg0.png

Any help will be appreciated.
 
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The limits are derived by looking at the original definition of the function. For 0<t<pi, f(t)=t^2. So as t->pi from below f(t)->pi^2. For pi<t<2*pi, f(t)=0. So as t->pi from above f(t)=0.
 

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