Fourier series of a train of gaussians

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SUMMARY

The Fourier series of a train of Gaussians is defined by the relationship: \mathcal{F} \{ \sum_{n=-\infty}^{+\infty}\frac{1}{\tau}e^{-\frac{\pi(x-n)^2}{\tau^2}} \} = \sum_{m=-\infty}^{+\infty}e^{-\pi\tau^2 m^2}\cos(2\pi mx). The Gaussian train is a periodic function with a period of 1. The challenge lies in computing the Fourier integral \int_0^{1} \left( \sum_{n=-\infty}^{+\infty}\frac{1}{\tau}e^{-\frac{\pi(x-n)^2}{\tau^2}} \right)e^{-i2\pi mx}dx, particularly due to the lack of a primitive function for Gaussians. The key consideration is whether the integral and summation can be interchanged, which requires uniform convergence and integrability over the interval [0,1].

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mnb96
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Hello,
I am following a proof in a book, in which the author makes use of the fact (without proving it) that the Fourier serie of a train of Gaussians is given by the following relationship:

\mathcal{F} \{ \sum_{n=-\infty}^{+\infty}\frac{1}{\tau}e^\frac{-\pi(x-n)^2}{\tau^2} \} = \sum_{m=-\infty}^{+\infty}e^{-\pi\tau^2 m^2}\cos(2\pi mx)

where n is an integer. I understand that the Gaussian train is a periodic function with period=1. However I don't quite understand how to compute its Fourier integral:

\int_0^{1} \left( \sum_{n=-\infty}^{+\infty}\frac{1}{\tau}e^\frac{-\pi(x-n)^2}{\tau^2} \right)e^{-i2\pi\ mx}dx

because Gaussians do not have a primitive function that allows computing that integral between [0,1].

Any hint?
 
Last edited:
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The question is whether integral and summation can be swapped, since beside that we only have a constant factor and two exponential functions which we can integrate. For that we need uniform convergence and integrability on ##[0,1]##.
 

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