Fourier transform and convolution, dirac function

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The discussion revolves around confusion regarding the convolution of two functions, E2.10 and E2.11, and its relation to the result E2.13. Participants are questioning the presence of a factor of 1/4 in E2.13, suggesting it may be incorrect. The convolution is defined as the integral of the product of the two functions, but discrepancies in the calculations have led to uncertainty. One participant attempts to compute the integral but does not arrive at the expected result, indicating a potential misunderstanding or error in the process. Overall, the conversation highlights the complexities of applying Fourier transforms and convolution, particularly with Dirac functions.
nightworrier
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Hi everyone,
I uploaded a solution about Fourier transform. At the solution of this problem, it states that make convolution. But i tried to do convolution but my result is not same with this result. When you do the convolution with 2.10 and 2.11, is the result 2.13 correct ? How is it done ? :S I am so confused.
 

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i really don't understand the basis of this problem

but from what you have posted if E2.9 to E2.12 is the way it is then E2.13 should be right

did you do the convolution of 2.10 with 2.11?
 
I try to do the convolution. But i think at E2.13 there shouldn't be 1/4. Maybe i do something wrong.
I said E2.10 x(f)
Then E2.11 y(f)

x(f)*y(f)=int(x(z).y(f-z)dz) right ? this is the convolution
so i put E2.11 into the integral. And i subsitute f to f-z the formula becomes
\frac{1}{2}int(\frac{1}{\frac{1}{2}+j2.pi.f}.[dirac(f-50-z)+dirac(f+50-z)]dz

then f-50-z=0 df=dz
z=f-50
i computed the integral than put z into these formula. But 1/4 not coming from there. Maybe i did something wrong
 
oops i don't get that 1/4 either, may be it is some typo in that sheet
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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