Fourier transform (integration)

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
12 replies · 2K views
gomes.
Messages
58
Reaction score
0
Got stuck in the second part, any help is appreciated, cheers.
 

Attachments

  • gsdgsdgsdgsdgsdg.jpg
    gsdgsdgsdgsdgsdg.jpg
    20.9 KB · Views: 545
Physics news on Phys.org
thanks, i tried doing that but I am not sure what to do with the u(t+4) bit.

btw is my first part correct? (question 1)
 

Attachments

  • 123.jpg
    123.jpg
    29.5 KB · Views: 452
thanks, but how would i integrate u(t+4)e^[t(-1-iw)-4]?

How do i deal with the u(t+4)?
 
sorry I am really stuck, u(t)?
 
thanks, i think i might have missed out on that lecture, which explains why.

Is what I've done correct?
 

Attachments

  • asgsdgsd.jpg
    asgsdgsd.jpg
    15.5 KB · Views: 435
sorry, I am really really stuck. What should the next line be, after the first line? Could someone possibly show me how to proceed from the 1st line?
 
Perhaps you misunderstood. I meant:

[tex]u(t) \ne \int_{-\infty}^\infty u(t+4) e^{t(-1-i\omega)-4}\,dt[/tex]

The integral in the second line is fine to calculate the Fourier transform you're looking for, but it's definitely not equal to u(t) as you wrote.

Try the substitution t'=t+4 to evaluate the integral.