I have been very briefly introduced to Fourier transformations but the topic was not explained especially well (or I just didn't understand it!)(adsbygoogle = window.adsbygoogle || []).push({});

We were shown the graphs with equations below and then their fourier transformation (RHS). I understand the one for cos(2pist) but NOT the sin(2pist).

Here is my reasoning:The sin wave shown has a constant frequency (that is larger than the cosine function; hence its frequency values are larger). It is possible to have a "-ve" frequency because waves can travel in both directions. I do not understand why the amplitude on the sin graph is negative though? If it was negative on both it would make sense but it isn't!

I know that both FT boil down to a cosine expression (as the sin expression is lost when integrating between infinities) and that makes it even more confusing for me! Please can someone help me understand. thanks

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# Fourier Transform of a sin(2pi*x)

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