- #1
LuisVela
- 33
- 0
Hello Everybody.
I gave a quick look onto the internet but i couldn't get anything interesting.
Heres my problem.
Im solving the differential equation given by:
[tex](-\Delta+k^2)^2u=\delta [/tex]
Where [tex]\delta[/tex] is the dirac delta distribuiton (and u is thought as a distribution as well)
The first step in the book is to apply FT to both sides of the equation...
The result is:
[tex](4\pi^2\xi^2+k^2)^2\hat{u}=1[/tex]
...I do know that the FT of the Laplacian is [tex]-4\pi^2\xi^2[/tex], but when the whole parenthesis is squared, i just can follow it. I don't know how to get that result...
BTW..whats the meaning of [tex]\Delta^2[/tex]?
Any ideas?
I gave a quick look onto the internet but i couldn't get anything interesting.
Heres my problem.
Im solving the differential equation given by:
[tex](-\Delta+k^2)^2u=\delta [/tex]
Where [tex]\delta[/tex] is the dirac delta distribuiton (and u is thought as a distribution as well)
The first step in the book is to apply FT to both sides of the equation...
The result is:
[tex](4\pi^2\xi^2+k^2)^2\hat{u}=1[/tex]
...I do know that the FT of the Laplacian is [tex]-4\pi^2\xi^2[/tex], but when the whole parenthesis is squared, i just can follow it. I don't know how to get that result...
BTW..whats the meaning of [tex]\Delta^2[/tex]?
Any ideas?
Last edited: