Fourier transform pair for u(t)

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SUMMARY

The Fourier transform pair for the unit step function u(t) is established as πδ(ω) + 1/(jω). The transform pair for the function u(t) - u(t-1) is derived using the time-shift theorem, resulting in the expression [πδ(ω) + 1/(jω)] - [πδ(ω-1) + 1/(j(ω-1))]. This application of the time-shift theorem is crucial for accurately determining the Fourier transform of shifted functions.

PREREQUISITES
  • Understanding of Fourier transforms and their properties
  • Familiarity with the Dirac delta function, δ(ω)
  • Knowledge of the time-shift theorem in signal processing
  • Basic concepts of complex frequency, jω
NEXT STEPS
  • Study the time-shift theorem in detail for Fourier transforms
  • Explore the properties of the Dirac delta function in signal processing
  • Learn about the Fourier transform of piecewise functions
  • Investigate the implications of complex frequency in signal analysis
USEFUL FOR

Students in electrical engineering, signal processing professionals, and anyone studying Fourier analysis and its applications in time-domain signal manipulation.

delta59
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Homework Statement

Ok I know Fourier transform pair for u(t) is pi*del(w)+1/(j*w)

Am I right to say the transform pair of u(t)-u(t-1) is [pi*del(w)+1/(j*w)]-[pi*del(w-1)+1/(j*(w-1)]

If not what is it?

thanks
 
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delta59 said:

Homework Statement




Ok I know Fourier transform pair for u(t) is pi*del(w)+1/(j*w)

Am I right to say the transform pair of u(t)-u(t-1) is [pi*del(w)+1/(j*w)]-[pi*del(w-1)+1/(j*(w-1)]

If not what is it?

thanks

No.
Use the time-shift theorem:
If G(f) = F{g(t)} then F{g(t-T)} = G(f)exp(-j2πfT). Here f = ω/2π.
 

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