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I thought the FT was about decomposing images into different frequencies. So I was showing the inverse of what I thought the FT and asking if it was correct as it was easier for me to show it this way.The sum should also have the vertical grey arm. But I just don't see how those pictures connect to the subject of FT.
Right and left (referrring to the images)What are R and L?
Ok, in addition then which of the two examples shown correctly represents the transformation between the spatial domain (right) and domain (left)You can use those pictures as an analogy to an FT, because FT is about summing functions of the form ##e^{ik_xx}## (for 1D) and ##e^{ik_xx}e^{ik_yy}## (for 2D) having certain amplitude distribution.
To me, the bottom picture seems to correspond to a pair of Fourier transform conjugates (can you see why?).Ok, in addition then which of the two examples shown correctly represents the transformation between the spatial domain (right) and domain (left)
Presumably because it is symmetrical about the centre of k-space.To me, the bottom picture seems to correspond to a pair of Fourier transform conjugates (can you see why?).
A way of justifying the bottom images is to do the math. The right picture of the bottom pair looks like it being composed of three delta functions. Mathematically, it readsPresumably because it is symmetrical about the centre of k-space.
But as the image only displays a single frequency I wasn't sure if I only needed to display two conugate pairs or lots
By your answer am I correct in assuming you think the bottom image is correct then?
Hi. Like I said I don't know any of the maths so I am learning everything conceptually.A way of justifying the bottom images is to do the math. The right picture of the bottom pair looks like it being composed of three delta functions. Mathematically, it reads
$$
f(x,y) = \delta(y) (\delta(x+a) + \delta(x) + \delta(x-a))
$$
Now Fourier transform ##f(x,y)## and see if you will get something that resembles the left picture.
FT is one subject of math, there is no other way to learn FT except by learning the maths.Like I said I don't know any of the maths so I am learning everything conceptually.
I see. well thank you for the confirmation but as I have a very limited knowledge of calculus it seems like it'll be a long time before I can prove why the bottom image is correct.FT is one subject of math, there is no other way to learn FT except by learning the maths.
Delta functions is a mathematical object usually used to represent a zero-dimensional point. In reality obviously there is no such object, however if a pinhole is much smaller compared to the wavelength of light illuminating it (in the case of the diffraction of light), it can be modeled as a delta function.
thanks :)The bottom image looks like the correct amplitude or power spectrum of the original image, which is based on the magnitude of the complex Fourier transform. However, you won't be able to reconstruct an image without a corresponding phase spectrum that comes from the argument of the same transform.