Fraction of electrons removed from a charged copper ball

[mysticbms]

Homework Statement

A 50.0 g ball of copper has a net charge of 2.00µC. What fraction of the copper’s electrons has been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

Homework Equations

1.00 C× (1proton)/(1.60×10^−19C)=6.25×10^18 protons
C = coloumb, the SI unit of charge

The Attempt at a Solution

I don't know where to begin. I haven't taken Chemistry in a long time so I'm pretty stumped.

 

[SammyS]

Homework Statement

A 50.0 g ball of copper has a net charge of 2.00µC. What fraction of the copper’s electrons has been removed? (Each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

Homework Equations

1.00 C× (1proton)/(1.60×10^−19C)=6.25×10^18 protons
C = coloumb, the SI unit of charge

The Attempt at a Solution

I don't know where to begin. I haven't taken Chemistry in a long time so I'm pretty stumped.

How many copper atoms are there in 63.5 grams of copper?

 

[gneill]

The atomic mass tells you the number of grams making up a mole of a substance. A mole is a specific number of particles (look up Avogadro's Number). So start by determining how many atoms comprise the 50.0 g ball of copper.EDIT: Beaten to the punch by SammyS!

 

[mysticbms]

Got it thanks.