How Many Electrons Are Removed from a Charged Copper Ball?

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SUMMARY

The discussion focuses on calculating the fraction of electrons removed from a charged copper ball with a diameter of 3.0 mm and a charge of 50 nC. The initial calculations included determining the number of electrons in the ball, estimated at 3.125 x 1011, and the volume of the ball, calculated as 1.414 x 10-8 m3. The participant encountered difficulties in reaching the correct answer, indicating a need for clarity in the calculation process.

PREREQUISITES
  • Understanding of basic physics concepts, specifically electrostatics.
  • Familiarity with the formula for volume of a sphere: v = 4/3 * π * r3.
  • Knowledge of the charge of an electron, approximately 1.6 x 10-19 C.
  • Ability to perform unit conversions and scientific notation calculations.
NEXT STEPS
  • Review the calculation of the volume of a sphere using the formula v = 4/3 * π * r3.
  • Learn how to calculate the total charge of electrons in a material based on its volume and density.
  • Explore the concept of charge density and its application in electrostatics.
  • Investigate methods for solving electrostatic problems involving charged objects.
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Students studying physics, particularly those focusing on electrostatics and charge calculations, as well as educators seeking to clarify concepts related to charged objects and electron behavior.

Mek8388
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Homework Statement


A 3.0mm-diameter copper ball is charged to 50nC.What fraction of its electrons have been removed? The density of copper is 8900kgm^3.


Homework Equations



d=m/v; v=4/3* pi r^3

The Attempt at a Solution



I worked through it and got 5.682 E -16, but that answer was wrong. I first found the number of electrons were in it (3.125 E 11). I then found the volume (1.414 E -8), and I think that's where I got stuck after that.
 
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So what did you try to do after that?
 
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Mek8388 said:

The Attempt at a Solution



I worked through it and got 5.682 E -16, but that answer was wrong. I first found the number of electrons were in it (3.125 E 11). I then found the volume (1.414 E -8), and I think that's where I got stuck after that.
Can you show the work you did to get those numbers? It would be easier to help you if you do that.
 

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