A small piece of aluminum(atomic number 13) contains 1015 . (The atomic number is the number of protons; it determines the (positive) electric charge of the nucleus and, thus, the number of electrons in a neutral atom.) If the piece of aluminum has a net positive charge of 3.0 micro Coulombs, what fraction of the electrons that the aluminum had when it was neutral would have had to be lost?
Avogaddro's number might be needed.
I am not sure exactly what I need as far as equations go.
I know what the answer is, but I am unsure of how to get it.
The Attempt at a Solution
I don't know how to work this problem fully. I have an idea, but I get stuck along the way.