France Unemployment Rate: MCQ Homework

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SUMMARY

The discussion centers on the interpretation of confidence intervals in relation to the unemployment rate in France, which was 13.4%. The key conclusion is that while the sample size of 100 allows for the use of a normal approximation, the answer key indicates that none of the proposed statements (A, B, C, D) are true, making E the correct answer. This is due to the inherent variability in random sampling, where even a 99% confidence interval may not include the true mean 1% of the time.

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  • Knowledge of simple random sampling (SRS)
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Homework Statement


One month the actual unemployment rate in France was 13.4%. If during that month you took a SRS of 100 Frenchmen and constructed a confidence interval estimate of the unemployment rate, which of the following would have been true?

A) The center of the interval was 13.4.
B) The interval contained 13.4.
C) A 99% confidence interval estimate contained 13.4.
D) The z-score of 13.4 was between +-2.576.
E) None of the above are true statements.

Homework Equations

The Attempt at a Solution


Since (unemployed, not unemployed) are 2 variables, I think the confidence interval for a proportion applies here. Since np = 13.4 > 10 and n(1-p) = 100 - 13.4 > 10, a normal distribution can be used to approximate the binomial distribution. Then shouldn't A, B, C, and D all be correct? It is a simple random sample, and the sample size is less than 10% of the French population. But the answer key says the exact opposite; E is the correct answer. Could somebody explain why? Thanks! :)
 
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little neutrino said:

Homework Statement


One month the actual unemployment rate in France was 13.4%. If during that month you took a SRS of 100 Frenchmen and constructed a confidence interval estimate of the unemployment rate, which of the following would have been true?

A) The center of the interval was 13.4.
B) The interval contained 13.4.
C) A 99% confidence interval estimate contained 13.4.
D) The z-score of 13.4 was between +-2.576.
E) None of the above are true statements.

Homework Equations

The Attempt at a Solution


Since (unemployed, not unemployed) are 2 variables, I think the confidence interval for a proportion applies here. Since np = 13.4 > 10 and n(1-p) = 100 - 13.4 > 10, a normal distribution can be used to approximate the binomial distribution. Then shouldn't A, B, C, and D all be correct? It is a simple random sample, and the sample size is less than 10% of the French population. But the answer key says the exact opposite; E is the correct answer. Could somebody explain why? Thanks! :)

Basically: in a random sample, the observed unemployment rate could vary from 0% to 100%. That is unlikely, but rare things DO happen. Even a 99% confidence interval could miss the 13.4% figure, because 99% confidence intervals will contain the true mean 99% of the time. That means they will fail to contain the true mean 1% of the time, and this could be one such time.
 
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Ray Vickson said:
Basically: in a random sample, the observed unemployment rate could vary from 0% to 100%. That is unlikely, but rare things DO happen. Even a 99% confidence interval could miss the 13.4% figure, because 99% confidence intervals will contain the true mean 99% of the time. That means they will fail to contain the true mean 1% of the time, and this could be one such time.

Ah I see... Thanks! :)
 

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