Free-Fall Acceleration and the Gravitational Force

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hold AP 2010
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When a falling meteoroid is at a distance above the Earth's surface of 3.00 times the Earth's radius, what is its acceleration due to the Earth's gravitation?
 
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as a rule of thumb the acceleration of gravity on Earth is 9.8m/s ... so unless they want you to do a lot of research i'd say that's it or 32ft/s
 
Denken said:
as a rule of thumb the acceleration of gravity on Earth is 9.8m/s ... so unless they want you to do a lot of research i'd say that's it or 32ft/s

Thats wrong

GMm/r

There is a gravitational constant x Earth's mass / radius.

Since we do not change the Earth's mass only radius

<< solution to schoolwork question deleted by berkeman >>
 
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Gnosis said:
Pardon brno17, but your answer is also incorrect.

The OP stated that a meter is falling from a distance above the Earth's surface of 3 Earth radii, which means a total of 4 Earth radii from the Earth's center of mass. That makes the acceleration by Earth's gravitational field per that distance (4 Earth radii)

<< solution to schoolwork question deleted by berkeman >>

Guys, even though this PF newbie posted in General Physics, this is almost certainly a schoolwork question, and the Homework Help rules apply. Please do not solve other students schoolwork questions for them. Giving hints and catching mistakes in their work is best. And if they don't show any effort (like this OP), please remind them that they need to show their work before we can provide tutorial help.

Thread moved to HH/Intro Physics.