A train is traveling 30 m/s in still air. The frequency of the train whistle is f = 250 Hz. What frequency is head by a passenger on a train moving in the opposite direction at 18 m/s and approaching the first train? The velocity of sound in air is 344 m/s.
F = [(1(+/-) (Velocity listener)/velocity sound) / (1(+/-) (Velocity source)/velocity sound)] *frequency
The Attempt at a Solution
Since the listener is moving towards the source and the source is moving towards the listener the forumula becomes
F = [(1+(Velocity listener)/velocity sound) / (1 - (Velocity source)/velocity sound)] *frequency
After plugging in the numbers i got 288Hz, is that correct?
it makes sense because the listener would hear a higher frequency b/c the source is moving towards the listener