Doppler effect w/ percentage frequency shift?

Click For Summary
SUMMARY

The discussion centers on calculating the speed of a train based on a 21% frequency shift of its whistle, utilizing the Doppler effect formula. The relevant equation is f’ = f [1/{1 ± (velocity of source/velocity of sound)}], where the speed of sound is given as 331.4 m/s. Participants clarify that the train's movement towards and away from the observer affects the perceived frequency, necessitating the use of both the approaching and receding scenarios to solve for the train's speed. The correct approach involves applying the frequency shift in both directions to derive the train's velocity accurately.

PREREQUISITES
  • Understanding of the Doppler effect and its applications
  • Familiarity with basic physics equations related to sound and motion
  • Knowledge of frequency, wavelength, and their relationship to speed
  • Ability to manipulate algebraic equations to solve for unknown variables
NEXT STEPS
  • Study the Doppler effect in detail, focusing on sound waves
  • Learn how to derive and apply the Doppler effect equations for moving sources
  • Explore practical examples of frequency shifts in various contexts, such as astronomy
  • Investigate the implications of frequency shifts in real-world applications, such as radar and medical imaging
USEFUL FOR

Students studying physics, educators teaching wave phenomena, and anyone interested in the practical applications of the Doppler effect in sound and motion analysis.

grantaere
Messages
15
Reaction score
0

Homework Statement


As you stand by a railroad track a train passes with its whistle blowing. As it passes, you hear a frequency shift equal to 21 % of the frequency of the whistle. How fast is the train moving. Express your answer in km/hr.(Speed of sound is 331.4 m/s)

Homework Equations


f’ = f [1/{1 ± (velocity of source/velocity of sound)}]
(source moving away from(+)/towards(-) observer)

The Attempt at a Solution


My initial attempt was simply to have
0.79 = [1/(1 + v of train)/331.4] but that seems to be incorrect... a clue from the teacher was that the train is first moving toward, then away from the observer, but I don't understand how that would affect the formula. Any hints? Thanks a ton in advance!
 
Physics news on Phys.org
a frequency shift equal to 21 % of the frequency of the whistle
the latter is probably the frequency f0 when the train is standing still. When the train comes at you you hear f' > f0 and when it moves away you hear f'' < f0. Why don't you follow teachers advice and see where it brings you ?
 

Similar threads

Replies
8
Views
1K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
14
Views
2K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K