Frequency heard, need someone to check

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SUMMARY

The discussion focuses on calculating the frequency of a train whistle heard by a passenger on a train moving towards the source. The formula used is F = [(1 + (Velocity listener)/velocity sound) / (1 - (Velocity source)/velocity sound)] * frequency. Given the parameters of the problem, with the source frequency at 250 Hz, the listener's speed at 18 m/s, and the source's speed at 30 m/s, the calculated frequency is 288 Hz. This result is confirmed as correct, as the Doppler effect indicates that the frequency increases when both the source and listener are moving towards each other.

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Homework Statement



A train is traveling 30 m/s in still air. The frequency of the train whistle is f = 250 Hz. What frequency is head by a passenger on a train moving in the opposite direction at 18 m/s and approaching the first train? The velocity of sound in air is 344 m/s.

Homework Equations



F = [(1(+/-) (Velocity listener)/velocity sound) / (1(+/-) (Velocity source)/velocity sound)] *frequency

The Attempt at a Solution



Since the listener is moving towards the source and the source is moving towards the listener the forumula becomes

F = [(1+(Velocity listener)/velocity sound) / (1 - (Velocity source)/velocity sound)] *frequency

After plugging in the numbers i got 288Hz, is that correct?

it makes sense because the listener would hear a higher frequency b/c the source is moving towards the listener

thanks
 
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