Friction and tension force- mass

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Homework Help Overview

The problem involves analyzing the forces acting on a mass (Brisket) being pulled up a ramp with friction. The ramp is inclined at 26.6° and has a coefficient of kinetic friction of 0.674. The tension force applied is 5060.8 N, and the mass is to be determined given the acceleration of 1.54 m/s².

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the forces acting on the mass, including gravitational components and friction. Questions arise regarding the derivation of the equation used and the correct setup for analyzing the forces.

Discussion Status

Some participants are attempting to break down the forces acting on the mass and express friction in terms of the normal force. There is a focus on setting up the net force equation and understanding the components of the forces involved. Guidance has been offered on how to approach the problem by considering all force components.

Contextual Notes

Participants express uncertainty about how to calculate the net force due to the need for the mass to determine the force components. There is an emphasis on the importance of correctly identifying the direction of forces and their contributions to the net force.

Paulbird20
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Friction and tension force-- mass

Homework Statement



In the real world, ramps aren't frictionless, so I had to drag Brisket up a ramp, slanted at 26.6° from the ground, that had a coefficient of kinetic friction = 0.674. I applied a tension force FR=5060.8N to my pet cow using the rope. Brisket moved up the ramp with an acceleration of magnitude 1.54m/s2. With this information, including friction on the ramp, what is Brisket's mass (in kg)?

Homework Equations


T= Uk*m*g/cos(angle)+Uksin(angle)
Fnet= ma


The Attempt at a Solution



I attempted to use the first equation

5060.8 = .674 * m * 9.8 / (cos(26.6)+ .674 sin(26.6)

using this equation i got 916.31 kg which is incorrect

any tips would be much appreciated thanks
 
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Paulbird20 said:

Homework Equations


T= Uk*m*g/cos(angle)+Uksin(angle)
Where does this formula come from?

Instead, just analyze the forces acting on the cow and apply Newton's 2nd law:
Fnet= ma
 


ok so the forces i have acting on the cow are:

mgsin(angle)
mgcos(angle)
mg
Friction(going up the incline)
N(force)

im not sure how to arrive at Fnet because i need the mass to be able to get the components of it
 


Paulbird20 said:
ok so the forces i have acting on the cow are:

mgsin(angle)
mgcos(angle)
mg
The weight (mg) can be broken into components.
Friction(going up the incline)
Express the friction in terms of the normal force and μ. Which way does it act?
N(force)
Don't forget the tension force.

im not sure how to arrive at Fnet because i need the mass to be able to get the components of it
Find Fnet by adding up all the force components parallel to the incline. (There are three such components.) Set up an equation using Newton's 2nd law and solve for the mass.
 

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