Friction causes a torque - then why do we sum it as a regular force?

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Homework Help Overview

The discussion revolves around the relationship between friction, torque, and forces in the context of Rigid Body Dynamics. The original poster expresses confusion about how friction can cause torque and how this relates to summing forces in problems involving both translational and rotational motion.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the distinction between torque and force, questioning how they interact in a system. The original poster seeks clarification on how to properly account for both translational forces and torque in their analysis.

Discussion Status

Some participants have provided insights into the nature of torque and its relationship with forces, emphasizing that torque should be treated separately from forces in free body diagrams. There is an ongoing exploration of how to balance torques and forces in static systems, with some participants suggesting that it is standard to include torques in free body diagrams when appropriate.

Contextual Notes

The original poster indicates they are new to the topic, which may contribute to their uncertainty regarding the concepts discussed. There is a mention of the need for additional resources to aid understanding.

Differentiate it
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Homework Statement
Friction causes a torque which is balanced out by the normal force. In most physics problems, we simply sum the applied force and friction, without considering anything about torque. I'm kind of new to Rigid Body Dynamics, so it'd be helpful if someone also explained how translational forces and torque are added in a system where there is both translational and rotational motion and/or sent links to some online resources. Thanks!
Relevant Equations
F=ma
Screenshot_20220829-112957.jpg
 
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Differentiate it said:
Homework Statement:: Friction causes a torque which is balanced out by the normal force. In most physics problems, we simply sum the applied force and friction, without considering anything about torque. I'm kind of new to Rigid Body Dynamics, so it'd be helpful if someone also explained how translational forces and torque are added in a system where there is both translational and rotational motion and/or sent links to some online resources. Thanks!
Relevant Equations:: F=ma

View attachment 313399
Torque is not a force so we do not include it on a FBD. We also don't sum it along with forces. (Check the units... the units for torque and force are different.)

I don't know what you mean by "Friction causes a torque which is balanced out by the normal force." A torque can only be balanced by another torque, not a force, and the torque due to the friction force is not canceled by the torque due to a normal force.

-Dan
 
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topsquark said:
Torque is not a force so we do not include it on a FBD. We also don't sum it along with forces. (Check the units... the units for torque and force are different.)

I don't know what you mean by "Friction causes a torque which is balanced out by the normal force." A torque can only be balanced by another torque, not a force, and the torque due to the friction force is not canceled by the torque due to a normal force.

-Dan
Right right, I'm just stupid, no probs no probs i get it
 
Differentiate it said:
Friction causes a torque which is balanced out by the normal force.
The torque caused by a force is always in respect of some chosen axis. In the diagram, using an axis at ground level, F applies a torque, Ff doesn’t.
The exception is when you have a pair of equal and opposite forces along parallel lines of application. In that case the net torque is the same no matter what axis you choose.
What you can say is that if the system is static then the torque due to the F, Ff pair balances the torque due to the N, mg pair.
Differentiate it said:
how translational forces and torque are added in a system
You add the forces to write Fnet=ma, and add the torques to write τnet=Iα.
topsquark said:
Torque is not a force so we do not include it on a FBD.
It's quite standard to include torques in an FBD where appropriate. In some posed questions, applied torques are specified as such, rather than as pairs of equal and opposite forces.
 
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Differentiate it said:
Right right, I'm just stupid, no probs no probs i get it
If you were stupid you wouldn't have asked us to help you clarify your question!

-Dan
 
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