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## Homework Statement

A car weighing 3220 lbs rounds a curve a 200 ft radius banked at an angle of 30deg. Find the friction force acting on the tires when the car is traveling at 60mph. Coefficient of friction is 0.9.

## Homework Equations

i rotated the axes such that y-axis is collinear with Fn

and x-axis is collinear with Ff

I tried equilibrating the y-components i get Fn = 4,724.6 lb , then Ff=(0.9)(4,724.6) = 4252.14 lb

while on equilibrating the x-components i got Ff= 1743.25lb

what does this implicate? is that possible? Please help. big Thanks!

PS. I have read from my book that Ff=(u)(Fn) is only true if skidding is impending or v is at maximum.. how come? so what's the meaning og 4252.14?