Friction, Forces, Coefficient of Friction (True/False) Simple

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SUMMARY

The discussion centers on the physics of pushing a filing cabinet across a rough floor with a coefficient of kinetic friction (μk) of 0.41. It is established that the force exerted on the cabinet equals the frictional force when moving at a constant speed. The incorrect assumptions include that doubling the force would maintain constant speed and that the exerted force could exceed the cabinet's weight. The normal force, which equals the cabinet's weight, plays a crucial role in determining the frictional force.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of friction and its coefficients, specifically kinetic friction
  • Familiarity with normal force and its relation to weight
  • Basic algebra for manipulating equations
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  • Study the concept of Newton's second law of motion in detail
  • Learn about static vs. kinetic friction and their applications
  • Explore the calculation of normal force in various scenarios
  • Investigate the effects of different surfaces on frictional forces
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Homework Statement



You are pushing a filing cabinet across a rough floor (μk = 0.41) in a straight line at a constant speed. Which of the following statements about the magnitudes of the forces acting on the filing cabinet are correct?
(T/F)the force that you exert on the filing cabinet will be equal to the frictional force on the cabinet
(T/F) the force that you exert on the filing cabinet will be more than the frictional force on the cabinet
(T/F)if you exerted twice the force, the cabinet would slide at a constant speed that is twice the original value
(T/F) the force that you exert on the filing cabinet will be more than its weight
(T/F)the force that you exert on the filing cabinet will be less than its weight

Homework Equations





The Attempt at a Solution



1. True I assume because it's at a constant speed
2. False I assume because then it would be accelerating?
3. False, I assume it would just be moving faster and accelerating not at constant speed
4. No idea
5. No idea

Help please, some explanations too would be great. I really appreciate it.
 
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The expression for frictional force is

f_k=\mu_k\mbox{N}

N is the normal force and in this case is equal to the weight of the cabinet. This information should help you with the last two questions.
 
Sweet, sometimes I'm a little slow, those last two were easy :P
 

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