Friction/Inclined plane question, help would be appreciated

  • Thread starter jami8337
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  • #1
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Friction/Inclined plane question, help would be appreciated :)

A box is sent sliding up a plane, inclined to the horizontal at 25.0◦ with an
initial speed of 3.0 m/s.
The coefficient of kinetic friction between the box
and the plane is 0.17. How far up the plane does the box go before coming to
rest



f=F[itex]\mu[/itex]



I rearange the equations using F=ma, using trig etc, and i dont get the answer which is supposedly 0.8m

Thanks
 

Answers and Replies

  • #2
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I rearange the equations using F=ma, using trig etc, and i dont get the answer which is supposedly 0.8m
Please explain how you got a result, and what the result was ...
 
  • #3
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I got, F=mgcos25
and fk(kinetic friction) = 0.17mgcos25

then
f=ma
hence
fk+mgsin25=f
ma=0.17mgcos25+mgsin25
a=0.17gcos25+gsin25
=5.66m/s^2

i then put that into v^2=u^2+2ax

and got x=0.14
 
  • #4
1,137
0


You did something wrong here
i then put that into v^2=u^2+2ax

and got x=0.14
Try it again ...
 
  • #5
26
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ah thank you, was for some reason doing a^2 :)
 
  • #6
1,137
0


ah thank you, was for some reason doing a^2 :)
You're Welcome !!
 

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