Friction - minimum value of force for movement

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Homework Help Overview

The discussion revolves around determining the minimum force required to initiate movement in a system involving two masses (M1 and M2) and friction. The context includes forces acting on wheels associated with these masses.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the wheels and the equilibrium conditions for the masses. Questions arise regarding the specific forces involved and the setup of the problem.

Discussion Status

Some participants have provided clarifications about the forces acting on the wheels, while others are exploring different aspects of the problem. There is an ongoing exchange of ideas, with no explicit consensus reached on the initial problem.

Contextual Notes

Participants express uncertainty about the forces acting on the wheels and the implications for the overall system. There is mention of a subsequent problem introduced by one participant, indicating a shift in focus.

voliseq
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Homework Statement



Determine the minimum value of the force F for which the systems start moving. Assume M1 = 1kg, M2 = 2kg, Us = 0.3.
Solution: F = 9; F = 6N

4dzes.jpg

My problem is that i don't know the forces acting on wheel.

Homework Equations





The Attempt at a Solution


M1 :
F - T = 0
M1g - N = 0
M2:
Fr - T = 0
M1g+M2g - N(from mass 1 and mass 2) = 0
 
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voliseq said:

Homework Statement



Determine the minimum value of the force F for which the systems start moving. Assume M1 = 1kg, M2 = 2kg, Us = 0.3.
Solution: F = 9; F = 6N

4dzes.jpg

My problem is that i don't know the forces acting on wheel.

Homework Equations



The Attempt at a Solution


M1 :
F - T = 0
M1g - N = 0
M2:
Fr - T = 0
M1g+M2g - N(from mass 1 and mass 2) = 0
Hello voliseq. Welcome to PF !

Which wheel (or wheels) ?
 
Hi Sammy, i mean those wheels attached to M1 (on first picture) and M2(on second picture).
 
voliseq said:
Hi Sammy, i mean those wheels attached to M1 (on first picture) and M2(on second picture).
The only forces acting on the wheels are normal (vertical) forces. The wheels are free to rotate, so the horizontal forces acting on them are zero.

Chet
 
Another problem

Thanks Chest it works, now i have got another problem to solve,
1. Here is the problem

f0d8p4.jpg


2. And here is my attempt at solution

2jb7fo1.jpg


I think something is wrong here as i can't get correct result
 
The members AB and BC need to be in equilibrium. In terms of P, what is the normal force exerted by the cylinder on AB? What is the normal force exerted by AB on the cylinder?

Chet
 
Chestermiller said:
The members AB and BC need to be in equilibrium. In terms of P, what is the normal force exerted by the cylinder on AB? What is the normal force exerted by AB on the cylinder?

Chet

N = Pcos30 ?
 
voliseq said:
N = Pcos30 ?
Please try again, taking moments about the pin.

Chet
 

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