3 pulleys - 2 masses on incline plane

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The discussion revolves around analyzing a system of three pulleys with two masses on an inclined plane to determine if the log will move up the ramp. Key calculations involve the forces acting on both blocks, with specific attention to the tension in the ropes and the effects of friction and incline angle. It is established that if one block descends, the log moves up the slope, but the distance moved by the log is half that of the descending block due to the pulley configuration. The relationship between the distances moved leads to the conclusion that the acceleration of the log is half that of the block. Ultimately, the analysis confirms that the log will indeed move up the ramp under the given conditions.
  • #31
haruspex said:
No, you suggested the log would ascend 2m, which means each x would lose 2m. That would mean you start with L=y+2x, And end with a string length (y+1)+2(x-2)=y+2x-3=L-3. The string has mysteriously shrunk by 3m.
Try another way of changing x when y increases by 1m.
(y+1) + 2 (x-0.5) = y + 2x = L ?
 
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  • #32
Saints-94 said:
(y+1) + 2 (x-0.5) = y + 2x = L ?
Right. The log moves up half the distance that the weight moves down.
Based on that, if the weight descends at speed v, how fast will the log slide up the slope?
 
  • #33
0.5v?
 
  • #34
Saints-94 said:
0.5v?
Ok! Now for the one we've been working towards ... how will the accelerations compare?
 
  • #35
Will the acceleration be twice as much at the block compared to the log?
 
  • #36
Saints-94 said:
Will the acceleration be twice as much at the block compared to the log?
Yes.
But now I should confess something. The question posed is whether the log will move. To answer that, you do not need to worry about how fast it will move. You can suppose that it does not move, so there are no accelerations, and see whether the balance of forces is consistent with that.
However, most multiple pulley questions do involve different accelerations, and I felt it was important you found out how to deal with these.
 

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