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Friction on a casing on a metal ring
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[QUOTE="Delphi51, post: 4514674, member: 162048"] Friction depends on the normal force, pressing the slider against the ring. That is the vector sum of the horizontal and vertical forces so I'm pretty sure the normal force magnitude is square root of {g² + (v²/R)²} all right. I'm playing with this, writing F = ma, μFn = ma, a = dv/dt = μF/m where F = the square root above. This looks like it might be possible to integrate with a substitution. If you could get it to say dw/sqrt(1 + w²) = constants * dt could you integrate it? If so, try to come up with a w substitution that incorporates the R and a g so you can factor out the g from the square root and leave just (1 + w²) under the square root. If you need a hint, try letting w = v*sqrt(R) and see how it simplifies. [/QUOTE]
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Friction on a casing on a metal ring
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