Friction problem -- 2 Blocks Sliding on a Surface

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Homework Help Overview

The problem involves two blocks, one with a mass of 2 kg and the other with a mass of 8 kg, initially at rest. A horizontal force of 10 N is applied to the smaller block, which is in contact with the larger block that has no friction with the surface. The discussion centers on determining the time it takes for the smaller block to reach the left edge of the larger block and the displacement of the larger block.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the forces acting on each block and the resulting accelerations. There are attempts to apply Newton's second law and kinematic equations, but some express uncertainty about the necessary variables. Questions arise regarding the relative motion between the two blocks and the applicability of certain principles, such as the Energy-Work Theorem.

Discussion Status

Participants are exploring various approaches to analyze the problem, including free body diagrams and relative motion. Some have provided insights on how to calculate accelerations, while others are questioning the validity of applying certain laws in this context. There is no explicit consensus on a single method or solution yet.

Contextual Notes

There is mention of constraints related to the lack of friction between the larger block and the surface, as well as the initial conditions of the blocks. The discussion reflects uncertainty about the necessary information to apply certain theorems effectively.

rf1
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Homework Statement


A block of mass m=2kg and one of mass M=8kg have initial velocity zero.
The friction coeffecient between m and M blocks is 0.3
Between block M and the surfasse there is no friction.
L=3 metres
F is a force constant and horizontal with magnitude 10 N, applied on block m and so block m starts to move and goes to left extremity of block M.
block M also moved as you can see in the image

1) How long does it takes to block m to arrive to left extremity of block M?

2? What is the value of the displacement of block M?

the image is:
http://s3.amazonaws.com/answer-board-image/79698f93-5a84-4194-ab39-782abe24edcd.png

Homework Equations

The Attempt at a Solution


[/B]
i put the forces applied in each block:
block 1:
x: ma1=F-F(of friction)
y: mg=Normal force 1

block 2:
x: Ma2=F(of friction)
y: Mg=Normal force 2

and then i took a2 (acceleration of block 2) = 0.735 m s^-2

i tried to use v^2=v^2 (initial) +2ax
but i don't know v neither x...any suggestion?
 
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rf1 said:

Homework Statement


A block of mass m=2kg and one of mass M=8kg have initial velocity zero.
The friction coeffecient between m and M blocks is 0.3
Between block M and the surfasse there is no friction.
L=3 metres
F is a force constant and horizontal with magnitude 10 N, applied on block m and so block m starts to move and goes to left extremity of block M.
block M also moved as you can see in the image

1) How long does it takes to block m to arrive to left extremity of block M?

2? What is the value of the displacement of block M?

the image is:
http://s3.amazonaws.com/answer-board-image/79698f93-5a84-4194-ab39-782abe24edcd.png

Homework Equations

The Attempt at a Solution


[/B]
i put the forces applied in each block:
block 1:
x: ma1=F-F(of friction)
y: mg=Normal force 1

block 2:
x: Ma2=F(of friction)
y: Mg=Normal force 2

and then i took a2 (acceleration of block 2) = 0.735 m s^-2

i tried to use v^2=v^2 (initial) +2ax
but i don't know v neither x...any suggestion?

What about looking first at the relative motion of block m with respect to block M?
 
Although you have an image, I suggest you to draw a free body diagram representing all the forces that are involved in the situation (in the image just appears one). Then see what happens. Is there constant velocity?

For there to be motion of something, there must be a force acting on that something.
 
rf1 said:
and then i took a2 (acceleration of block 2) = 0.735 m s^-2
Good. What's the acceleration of block 1?

rf1 said:
i tried to use v^2=v^2 (initial) +2ax
but i don't know v neither x...any suggestion?
Well, you do know the distance... the relative distance. Since you don't know v, you might want to choose another kinematic formula.
 
Doc Al said:
Good. What's the acceleration of block 1?Well, you do know the distance... the relative distance. Since you don't know v, you might want to choose another kinematic formula.

I can't calculate acceleration of block 1 because it is in an accelerated frame and so the second law of Newton is not valid

I tried to use Energy-Work Theorem but i can't because i don't have enough information to use it
 
rf1 said:
I can't calculate acceleration of block 1 because it is in an accelerated frame and so the second law of Newton is not valid

I tried to use Energy-Work Theorem but i can't because i don't have enough information to use it

Suppose two racing cars started at the same time. One accelerated at ##a \ ms^{-2}## and one accelrated at ##b \ ms^{-2}## and you measured the distance between them over time.

Suppose you repeated this and the first car failed to start and the second car accelerated at ##(b-a) \ ms^{-2}## and you measured the distance between them over time.

Would there be any difference?
 
rf1 said:
I can't calculate acceleration of block 1 because it is in an accelerated frame and so the second law of Newton is not valid
You can calculate the acceleration of block 1 exactly as you calculated the acceleration of block 2: By applying Newton's 2nd law from the inertial frame of the ground. Those accelerations will be with respect to the ground. It's up to you to figure out the relative acceleration of block 1 with respect to block 2.

rf1 said:
I tried to use Energy-Work Theorem but i can't because i don't have enough information to use it
You won't need the work-energy theorem; stick to Newton's 2nd law and kinematics.
 

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