Friction problem again Okay today is not my day

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SUMMARY

The discussion focuses on calculating the maximum required acceleration of a train to prevent a passenger from slipping, given a coefficient of friction of 0.47. The fundamental equation used is Newton's second law, F=ma, which relates force, mass, and acceleration. The key insight is that the passenger experiences the same acceleration as the train, allowing for the formulation of an equation that incorporates the frictional force. By applying Newton's laws correctly, the unknown acceleration can be determined without additional information about the train's acceleration.

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Homework Statement



A passennger is standing without slipping in a forward accelerating train. The coeffeciant of the feet and the floor is 0.47. Determine the maximum required acceleration of the train relative to the track if the passenger is not to slip

Homework Equations



F=ma

The Attempt at a Solution



I know that acceleration = 0, but when I rearrange the equations. I end up with
F(a) = ma + (mu)mg. But I only know (mu)... so I end up not being able to solve it.
 
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vysis said:

Homework Statement



A passennger is standing without slipping in a forward accelerating train. The coeffeciant of the feet and the floor is 0.47. Determine the maximum required acceleration of the train relative to the track if the passenger is not to slip

Homework Equations



F=ma

The Attempt at a Solution



I know that acceleration = 0, but when I rearrange the equations. I end up with
F(a) = ma + (mu)mg. But I only know (mu)... so I end up not being able to solve it.

If you consider things from the reference frame of the ground, the man is accelerating with the same acceleration as the train. Write out Newton's law in that case. What forces are acting on him? Once you use that in Newton's law, you should find that you only have one unknown left in your equation.
 
but I'm not given the train's acceleration... am I missing something here =/?
 

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