Friction, speed, and radius of a curve?

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SUMMARY

The discussion focuses on calculating the speed at which a car will begin to slide while rounding a level curve with a radius of 39.3 meters, given a coefficient of static friction of 0.789. The relevant equations include the formula for centripetal acceleration, a = v²/r, and the maximum static frictional force, f(s,max) = μ(s) * F(n). The frictional force must equal the centripetal force for the car to remain on the curve without sliding.

PREREQUISITES
  • Understanding of uniform circular motion and centripetal acceleration
  • Knowledge of static friction and its coefficient
  • Familiarity with Newton's laws of motion
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate the maximum speed using the equation v = sqrt(μ(s) * g * r)
  • Explore the effects of varying the radius on the required speed
  • Investigate the role of negative lift in vehicle dynamics
  • Learn about frictional forces in different road conditions
USEFUL FOR

Students studying physics, automotive engineers, and anyone interested in vehicle dynamics and safety on curves.

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Homework Statement



Suppose the coefficient of static friction between the road and the tires on a car is 0.789 and the car has no negative lift. What speed will put the car on the verge of sliding as it rounds a level curve of 39.3 m radius?

Homework Equations



i know the equation for uniform circular motion is a=(v^2)/r
verge of sliding means f(s,max)=mu(s)*F(n)

The Attempt at a Solution



and seriously, I have no idea where to start.
 
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Well shouldn't the frictional force provide the centripetal force required?
 

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