Static friction, car going around a turn

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SUMMARY

The discussion centers on calculating the speed at which a car will begin to slide while navigating a level curve with a radius of 30.5 meters, given a coefficient of static friction of 0.60. The relevant equations include centripetal force (F = MV²/R) and the frictional force (F_friction = μmg). The static friction provides the necessary centripetal force to keep the car on the curve, leading to the conclusion that the maximum speed can be derived from these equations.

PREREQUISITES
  • Understanding of centripetal motion and forces
  • Knowledge of static friction and its coefficient
  • Familiarity with basic physics equations related to motion
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Calculate the maximum speed using the equation V = √(μgR)
  • Explore the effects of varying the radius of the curve on the maximum speed
  • Investigate the role of negative lift in vehicle dynamics
  • Learn about the impact of tire materials on the coefficient of static friction
USEFUL FOR

Physics students, automotive engineers, and anyone interested in vehicle dynamics and safety while navigating curves.

mmiller9913
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Homework Statement



Suppose the coefficient of static friction between the road and the tires on a car is .60 and the car has no negative lift. What speed will put the car on the verge of sliding as it rounds a level curve 30.5m in radius.

Homework Equations


A=V^2/R
F=MV^2/R


The Attempt at a Solution


I've stared at this problem and have absolutely no idea where to start. You can't find the static friction since you don't know the normal force. You can't really use any of the centirpital motion equations since you don't have enough values for the variables
 
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Well your static friction would provide the centripetal force.

Ffriction = μmg

Fcentripetal = mv2/r
 

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