Friction - truck on a slippery road

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SUMMARY

The discussion focuses on calculating the stopping distance of a truck skidding on a slippery road with a speed of 40 m/s and a coefficient of kinetic friction of 0.30. The relevant equations include Newton's second law (F=ma) and the kinematic equation V^2 = V_initial^2 + 2ax. The solution involves determining the acceleration due to friction and applying the kinematic equation to find the skid distance. The correct approach yields a stopping distance based on the derived acceleration from the frictional force.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with kinematic equations
  • Knowledge of friction coefficients and their implications
  • Basic algebra for solving equations
NEXT STEPS
  • Calculate stopping distances using different coefficients of friction
  • Explore the effects of varying initial speeds on stopping distance
  • Learn about the physics of skidding and tire-road interactions
  • Investigate real-world applications of friction in vehicle safety systems
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Students studying physics, automotive engineers, and anyone interested in vehicle dynamics and safety calculations.

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Homework Statement


A truck is traveling at 40 m/s on a slippery road. The driver slams on the brakes and the truck starts to skid. If the coefficient of kinetic friction between the tires and the road is 0.30, how far will the truck skid before stopping?


Homework Equations



ma=-ug
V^2 = Vintial +2at
x = (v^2 + Vintial^2)/2a

The Attempt at a Solution


would it be 40^2 divided by .6(9.8m/s)
 
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Use F=ma in the x-direction to get the acceleration, and then your third equation gets you all the way home.
 

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