Frictional Forces and 1D Motion

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The discussion focuses on calculating the minimum time and distance required for a car to stop on a wet concrete road, given a coefficient of kinetic friction of 0.5 and an initial speed of 30 mi/hr. The user expresses confusion about the appropriate equations to use for determining stopping time and distance, noting that the braking force remains constant regardless of initial speed. They highlight the relationship between speed and stopping distance, emphasizing that while the retarding force is constant, the stopping distance varies predictably with speed. The user seeks clarification on how to approach the problem using the concepts of friction and acceleration. Understanding these principles is crucial for solving the problem accurately.
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INTRODUCTION:
This is a problem from my Introduction to Physical Science class using "Conceptual Physics" 10th Ed.by Paul G. Hewitt

EXACT PROBLEM:
"The coefficient of kinetic friction between a rubber tire and a wet concrete road is 0.5."

PROBLEMS FACED:
a) Find the minimum time in which a car whose initial speed is 30 mi/hr can come to a stop on such a road.
b) What distance will the car cover in this time?

MY THOUGHTS:
I know I have a coefficient of friction & V0 and Vf. Beyond that, I don't know how to look for the time it will take. What equation am I supposed to be using?
 
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Lets take this a step at a time. To stop, you need a negative acceleration. Assume the brakes are aplied full force as in panic stop.

I still find the fact that speed/velocity never enters the eqn curious: that is the braking force is constant. Whether from 100mph or 5mph the retarding force is the same. So its like a baseball thrown upwards at different speeds.:The stopping distance depends on velocity, but its predictable. This is key.

So in a horizontal position, the frictional force depends on the negative force/acceleration generated by the weight times the coeffiecient of friction. Any help?
 
Last edited:
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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